6b^2+9b-15=0

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Solution for 6b^2+9b-15=0 equation:



6b^2+9b-15=0
a = 6; b = 9; c = -15;
Δ = b2-4ac
Δ = 92-4·6·(-15)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-21}{2*6}=\frac{-30}{12} =-2+1/2 $
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+21}{2*6}=\frac{12}{12} =1 $

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